Question

A can do a piece of work in 10 days and B can do it in 15 days. A worked for 4 days and left. How many
days will B alone take to complete the remaining work?​

Answer 1

Step-by-step explanation:

A-10

B-15

total work= LCM(10,15)=30

A can do amount of work in a day=30/10=3

B can do amount of work in a day=30/15=2.

Both worked for 4 days together, total work done by them in 4 days

=3×4+2×4

=12+8

=20

Amount of work left

=30-20

10

Now A has left, so left work will be done all by B himself

so, No of days in which B will complete his work

=work left/work done by B in a day

=10/2

=5.