A can do a piece of work in 10 days and b can do it in 15 days and c can do it 20 days. they started the work together and a leaves after 2 days and b leaves after 4 days from the beginning. how long will work lost?
Answers
Answered by
0
hi friends in this problem we solve
simple methods
by lcm method
A = 10 , B = 15 , C = 20
LCM is total work
lcm = 60 unit
one days work in unit of each
60/10 = 6 unit
60/15 = 4 unit
60/20 = 3 unit
A + B + C = 6 + 4 + 3 = 13 unit per days
work together 2 days
13 × 2 = 26 unit done
after 2 days a
Now B + C = 4 + 3 = 7 unit
together do 4 days
7 × 4 = 28 unit
work done = 26 + 28 = 54 unit
work remaining = 60 - 54 = 6 unit
C do in = 6/3 = 2 days
total work done in
2 + 4 + 2 = 8 days
simple methods
by lcm method
A = 10 , B = 15 , C = 20
LCM is total work
lcm = 60 unit
one days work in unit of each
60/10 = 6 unit
60/15 = 4 unit
60/20 = 3 unit
A + B + C = 6 + 4 + 3 = 13 unit per days
work together 2 days
13 × 2 = 26 unit done
after 2 days a
Now B + C = 4 + 3 = 7 unit
together do 4 days
7 × 4 = 28 unit
work done = 26 + 28 = 54 unit
work remaining = 60 - 54 = 6 unit
C do in = 6/3 = 2 days
total work done in
2 + 4 + 2 = 8 days
Similar questions