A can do a piece of work in 10 days and b can do it in 15 days how much time it will take them both to do same amount of work
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Answer: 6 days
Step-by-step explanation:
Let 'x' be the no. of days taken by both to do the same work.
Work done by A in one day=1/10
Work done by B in one day=1/15
Therefore,
Work done by both in one day
=1/10 + 1/15 = 1/x
LCM of 10 and 15 is 30
Therefore
3/30 + 2/30 = 1/x
i.e. 5/30 = 1/x
i.e. 1/6 = 1/x
i.e. x=6
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