A can do a piece of work in 10 days and B can do
same work in 15 days. Both Ą and B start the work
and after 3 days B left. In how many days will A do
the remaining work?
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Step-by-step explanation:
lcm of 10, 15 = 30
A:B = 10:15 = 2:3 ratio of days
A:B = 15:10 = 3:2 ratio of work
total work = 3+2 =5 parts of work
A+B = 5/lcm = 5/30 =1/6 part of work
for 3 days work
work done by A+B = 3× 1/6 =3/6 = 1/2
remaining work = 1-1/2 = 1/2
so as B left, A does the remaining work
A does one work in 10 days
A does 1/2 work in 10×1/2 = 5 days
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