A can do a piece of work in 10 days and B can do
same work in 15 days. Both A and B start the work
and after 3 days B left. In how many days will A do
the remaining work?
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Answer:
A takes 15 days => A does 2 parts/day
B takes 10 days => B does 3 parts/day
They worked together for 2 days
Work done by (A + B) = 5 parts/day
So, work completed in 2 days = 2×5 = 10 parts
Remaining work = 20 parts
This remaining work will be done by A
So, time taken = 202 = 10 days
Thus, the whole work was completed in 12 days. (
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