Question

A can do a piece of work in 10 days
and B can do the same piece of work
in 20 days. They start the work
together, but after 5 days A leaves. B
will do the remaining piece of work in​

Answer 1

Answer:

5 days

Step-by-step explanation:

part of work done by A in 1 day = 1/10

part of work done by B in 1 day = 1/20

part of work done by both in 1 day

$= \frac{1}{10} + \frac{1}{20}$

$= \frac{2 + 1}{20}$

$= \frac{3}{20}$

work done by both in 5 days

$= 5 \times \frac{3}{20}$

$= \frac{15}{20}$

remaining part =

$= 1 - \frac{15}{20}$

$= \frac{5}{20}$

$= 5 \times \frac{1}{20}$

remaining work done by B in = 5 days