A can do a piece of work in 10 days, and B can do the same work in 20 days. With the help of C, they finished the work in 4 days. C can do the work in how many days, working alone?
Answers
Answered by
3
Answer:
hii
your answer is here !
Step-by-step explanation:
Their combined 4 day work = 4(1/10 + 1/15) = 12/20 = 3/5.
Remaining work = 1 – 3/5 = ⅖.
This means C did 2/5 work in 4 days, hence he can finish the complete work in 5/2 × 4 = 10 days.
follow me !
Answered by
4
A can do work = 10days
A 1 day work = 1/10 days
B can do work = 20 days
B one day work = 1/20 days
let C can do work x days
C 1 day work = 1/x days
A,B,and C together 1 day work = 1/x + 1/10+1/20=( 20 + 3x )/20x
According to question
20x /(20 + 3x) = 4
20x = 80 + 12x
8x = 80
x = 10
Similar questions