Math, asked by nitin17367, 1 year ago

A can do a piece of work in 10 days, and B can do the same work in 20 days. With the help of C, they finished the work in 4 days. C can do the work in how many days, working alone?​

Answers

Answered by Anonymous
3

Answer:

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your answer is here !

Step-by-step explanation:

Their combined 4 day work = 4(1/10 + 1/15) = 12/20 = 3/5.

Remaining work = 1 – 3/5 = ⅖.

This means C did 2/5 work in 4 days, hence he can finish the complete work in 5/2 × 4 = 10 days.

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Answered by Anonymous
4

A can do work = 10days

A 1 day work = 1/10 days

B can do work = 20 days

B one day work = 1/20 days

let C can do work x days

C 1 day work = 1/x days

A,B,and C together 1 day work = 1/x + 1/10+1/20=( 20 + 3x )/20x

According to question

20x /(20 + 3x) = 4

20x = 80 + 12x

8x = 80

x = 10

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