Question

A can do a piece of work in 10 days and b can do the same work in 20 days with the help of c they finish the work in 5 days how long will it take for see alone to finish the work

Answer 1

A= 30 days

B= 20 days

C= 60 days

The equations are (days)(work/day) = job

10 days (A work/day) + 10 days (B work/day) + 10 days (c work/day) = job

10A +10B + 10c = job

12A +12B= job

20A +20C=job

Then it is simple algebra… from the last equation 10A + 10C = 1/2 job, then substitute into the first equation so

10B + (10A +10C) = job

10B +1/2job = job

10 B = 1/2 job

20 B = job … it takes B 20 days to do the job, etc. etc.

Hope it helps ✌✌❤