A can do a piece of work in 10 days and B in 12 days. With help of C, they finish the work in 4 days. In how many days C alone can do the same work?
A) 12 B) 15 C) 18 D) 24
Answers
- 'A' can do a piece of work in 10 days.
- 'B' can do the work in 12 days.
- With help of 'C', they finish the work in 4 days.
- Days in which C alone can do the same work.
'A' alone can complete a work in 10 days
'B' alone can complete a work in 12 days
Let 'x' be the days taken by the 'C' to done the same work
'C' along with 'A' and 'B' to complete a work in 4 days
Hence 'C' will take 15 days to do the work alone.
Answer:
15 days.
Step-by-step explanation:
Time taken by A to do the work = 10 days.
So his one day's work will be 1/10.
Similarly B's one day work will be the reciprocal of the time taken by him.
B's one day's work = 1/12.
Let time taken by C be x.
Therefore, C's one day work = 1/x.
If all of them work together, they complete the work in 4 days.
So together their one day's work will be 1/4.
But their one day's work is given as, 1/10+1/12+1/x
=(6x+5x+60)/60.
Therefore 1/4 = (11x+60)/60x
15x = 11x+60
x = 15 days
Therefore the time taken by C is 15 days.
HOPE IT HELPS
PLEASE MARK AS BRAINLIEST