A can do a piece of work in 10 days and b in 18 days, and a, b and c can together do it in 4 days. In what time would c alone do it?
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Answer: 180/17 days or 10 10/17 days (mixed fraction)
Step-by-step explanation:
Work done by A in 1 day = 1/10
Work done by b in 1 day = 1/18
Work done by A, B and C in 1 day = 1/4
Work done by C in 1 day = Work done by A, B and C in 1 day - (Work done by A 1 day + Work done by B in 1 day0
= 1/4 - (1/10 + 1/18)
= 1/4 - 28/180
= 45/180 - 28/180
= 17/180
No. of days taken by C to complete work = 180/17
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