A can do a piece of work in 10 days and B in 20 days . they begin together but A leaves 2 days before the completion of the work . In how many days will the whole work be completed.
solve it by taking variables as x and y
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Step-by-step explanation:
(a+b)'s one day work=(1/10+1/20)=3/20
according to the ques B alone did the work in last 2 days so B's 2 days work=2*1/20=1/10.
(1-1/10)=9/10 is the work which A and B together did.
no. of days=(9/10)/(3/20)=6.
total days=6+2=8 days.
ans:8 days.
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