A can do a piece of work in 10 days and B in 20 days they begin together but A leaves 2 days before the completion of the work. In how many days will the whole work be completed
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Answer:
10 days
Step-by-step explanation:
A= in 10 days
then A's work in 1 day=1/10
B=in 20 days
then B's work in 1 day= 1/20
Both A and B's work in 1 day=
(1/10)+(1/20)
=3/20
After 2 day work done =
3×2/10
=3/5
remaining work after 2 days
1-(3/5)
=2/5
Remaining work to be done by B will be =
B can do whole work in 20 days
B can do 2/5 work in 20×2/5
=8 days
So total work will be done in
8+2 =10 days
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