Question

) A can do a piece of work in 10 days and B in 20 days. They begin together but A leaves 2 days before the completion of the work. In how many days will the whole work be completed?​

Answer 1

Answer:

Given that

A can do the work in 10 days

B can do the same work in 20 days

so,

Both one day work = A's one day work = 1

10

B's one day work = 1

20

now, both work=

1 + 1 = 2+1 = 3

10 20 20 20

now, they both will do 3 work in one day

20

but

A leaves the job before 2 days of completion

so total work by both in one day = 3

20

now their total work = 20

3

now 20-6 = 14

3 3

hence the work will completed in = 14 days

hence the work will completed in = 14 days 3