A can do a piece of work in 10 days. B can do it in 20 days. They start together, but after 5 days A leaves off. B will complete the remaining in?
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Answer:
Step-by-step explanation:
A will do 1/10th work in 1 day
B will do 1/20th work in 1 day
work together
1/10+1/20=3/20
5 days work=5*3/20=15/20=3/4
remianing work=1/4
b 1 day----->1/20
?---------------->1/4
5 days
Answered by
0
Answer:
A takes 10 days
1 day work of A=1/10
B takes 20 days
1 day work of B= 1/20
1 day work if A and B together = 1/10+1/20=3/20
they worked together for 5 days
work completed =3/20X5=3/4
remaining work = 1-3/4=1/4
time taken by B to complete 1/4 work=
¼/1/20
=1/4X20
=5 days
therefore B takes 5 days to complete remaining work
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