A can do a piece of work in 10 days B in 18 days A and B , C in 4 days . in what time would C do it alone?
Answers
Step-by-step explanation:
work done = 60 units
1) Find how much work A did in a single day.
60/10 = 6
A can do 6 units a day.
2) Find how much work B did in a single day.
60/18 = 3.33
B can do 3.33 units a day.
3) Find how much work C did in a single day
A works: 6 x 4 = 24 units
B works: 3.33 x 4 = 13.32 units
24 + 13.32 = 37.32 ( add the units of A and B)
60 - 37.32 = 22.68 (subtract it from the whole work units)
C works = 22.68 units
22.68 / 4 = 5.67 (divide it by 4, because C work for 4 days)
C can do 5.67 units a day.
4) How many days can C finish the work.
60 / 5.67 = 10.58
C can finish the work in 11 days.
( we rounded it off because in this type of situation remainder is not allowed)
Answer:
C can do a piece of work in 11 days.
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