A can do a piece of work in 10 days m,B in 12 days and C in 15 days.All begin together but A leaves the work after 2 days and B leaves 3 days before the work is finished. How long did the work last.
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Answer:
7
Step-by-step explanation:
LCM of (10 , 12 , 15) = 60
Efficiency , A : B : C = 6 : 5 : 4
Now , 4T + (T-3)*5 + 2*6 = 60
=> 4T + 5T - 15 + 12 = 60
=> 9T = 63
=> T = 7 days (Ans.)
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