A can do a piece of work in 10days and B in 20 days they begin together but A leaves 2 days before the completion of the work in how many days will the whole work be complete
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Work doe by A in 1 -day = 1/10
Work done by B in 1 - day = 1/20
Total work done = 1/10 + 1/20 = 3/20.
It is said that A leaves 2 days before the completion of work.
=> 2 * (1/20) = 1/10.
Remaining work = 1 - 1/10 = 9/10.
Number of days worked = (9/10)/(3/20)
=> 6.
As A leaves 2 days before.
Total number of days = 6 + 2 = 8.
Hence,Number of days it took = 8 days.
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