Math, asked by rohan2453, 9 months ago

A can do a piece of work in 12 days and B alone can do it in 16 days they worked together on it for 3 days and then A left.how long did B take to finish the remaining work?​

Answers

Answered by Rockysingh07
11

Bonjour !

A and B do work together for 3 days :

= 3(1/12 + 1/16)

= 3(4+3/48)

= 3×7/48

= 7/16

Remaining work : 1- 7/16

= 9/16

Time taken by B = 9/16× 16

= 9 days

B take 9 days to finish the remaining work .

I hope it will helps you to guide and and and mark me brainliest

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