A can do a piece of work in 12 days and B alone can do it in 16 days. They worked together on it for 3 days and A left. How long did B take to finish the remaining work?
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1
Answer:
B will take 9 days to finish the remaining work
Step-by-step explanation:
A can do part of work in 1 day = \frac{1}{12}
12
1
B can do part of work in 1 day = \frac{1}{16}
16
1
(A+B)'s 1 day work = \frac{1}{12}+\frac{1}{16}=\frac{7}{48}
12
1
+
16
1
=
48
7
(A+B)'s 3 days work =\frac{7}{48} \times 3=\frac{7}{16}
48
7
×3=
16
7
Remaining work = 1-\frac{7}{16}=\frac{9}{16}1−
16
7
=
16
9
B can do 1 work in days = 16
B can do \frac{9}{16}
16
9
work in days = \frac{9}{16} \times 16=9
16
9
×16=9
Hence B will take 9 days to finish the remaining work
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1
This is the answer I think so
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