Question

A can do a piece of work in 12 days and B alone can do it in 16 days. They worked together on it for 3 days and then A left. How long did B take to finish the remaining work?​

Answer 1

9 days b will take as together they complete 21 work out of 48 total work

Answer 2

B will take 9 days to finish the remaining work

Step-by-step explanation:

A can do part of work in 1 day = $\frac{1}{12}$

B can do part of work in 1 day = $\frac{1}{16}$

(A+B)'s 1 day work = $\frac{1}{12}+\frac{1}{16}=\frac{7}{48}$

(A+B)'s 3 days work =$\frac{7}{48} \times 3=\frac{7}{16}$

Remaining work = $1-\frac{7}{16}=\frac{9}{16}$

B can do 1 work in days = 16

B can do $\frac{9}{16}$ work in days = $\frac{9}{16} \times 16=9$

Hence B will take 9 days to finish the remaining work

#Learn more:

A can do a piece of work in 12 days and B alone can do it in 16 days. They worked together on it for 3 days and then A left. How long did B take to finish the remaining work?​

https://brainly.in/question/12486627