A can do a piece of work in 12 days and b can do the same work in 20 days they work together for 3 day and then a goes away. In how many days will be finished the work?
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In 1 day A and B together can do(1/12+1/20) of the work=1/12+1/20
=5+3/60
=8/60
=2/15
In 3 days A and B can do=3×2/15
=2/5 of the work
Remaining work=1/1-2/15
=3/5
Since,B can do 1/20 of the work in 1 day, therefore the number of days he will take to finish 3/5 of the work=3/5÷1/20
=3/5×20/1
=12 days
So,
ANS=12 days
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