A can do a piece of work in 12 days and B can do the same in 18 days how many days they will take to do the work together
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Answered by
1
Answer:
6 days
Step-by-step explanation:
LCM of 12 and 18 = 36
total work = 36 unit
1 day work of A = 36/12 = 3 unit
1 day work of B = 36/18 = 2 unit
B alone worked for 3 days ( as A left the work 3 days before so, B has to do the left work alone for three days )
- total work done by B alone in 3 days = 3 x 2 unit = 6 unit work,
- total work left = 36 unit - 6 unit = 30 unit
- 30 units work is done by both A and B
Hence, no. of days to complete the remaining work = 30/total work done by A and B
- 30/5 = 6 days
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0
Answer:
hello Sirisha ❤️
Good morning
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