Question

a can do a piece of work in 12 days and b in 18 days .they worked together for 4days when a fell ill and b had to complete the remaining work . in how many days was the work completely

Answer 1

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Answer 2

Given:

a can do a piece of work in 12 days and b in 18 days .

They worked together for 4days when a fell ill and b had to complete the remaining work .

To Find:

in how many days was the work completely

Solution:

a's 1 day work =$\frac{1}{12}$

b's 1 day work =$\frac{1}{18}$

(a+b)'s 1 day work =$\frac{1}{12}+\frac{1}{18}=\frac{5}{36}$

(a+b)'s 4 days work =$\frac{5 \times 4}{36}=\frac{20}{36}$

Remaining work = $1-\frac{20}{36}=\frac{16}{36}$

b can do complete work in days = 18

b can do 16/36  work in days =$18 \times \frac{16}{36}=8$

Hence The work completes in 8 more days