a can do a piece of work in 12 days B can do it in 15 days and C can do it in 20 days they start the work together but after 2 days a leaves of and she left to day before the completion of the work B will do the remaining work how many total day complete the work
Answers
Answered by
2
Answer:
8 days
Step-by-step explanation:
To find the total work to be done, find the LCM of 12,15,20 = 60
Therefore, work done by A in a day = 60 / 12 = 5
work done by B in a day = 60 / 15 = 4
work done by C in a day = 60 / 20 = 3
Work completed in the first two days = 2 * (5+4+3) = 24
Work done in last two days by B alone = 2 * 4 = 8
Remaining work = 60 - 24 - 8 =28, which was done by B and C
Time required for B and C to complete this portion of work = 28/(4+3) = 4
Therefore, the total time took to complete the work = 2+4+2 = 8 days
Similar questions