Question

A can do a piece of work in 12 days. B can do this work in 16 days. A started the work alone. After how many days should B join him, so that the work is finished in 9 days?​

Answer 1

Answer:

hlo

your answer is here !

Step-by-step explanation:

A's work in 9 days = 9/12 = 3/4. Remaining work = 1/4.

This work was done by B in 1/4 × 16 = 4 days.

∴ B would have joined A after 9 – 4 = 5 days

$follow \: \: \: me$

Answer 2

Lets take total work as 48(LCM of 12 and 16),

So, A does 4 works in 1 day and B does 3 works in 1 day,

Lets take x days is taken by A and 9-x days by A+B to do 48 works,

work done by A will be 4x and work done by A+B will be 7(9-x),

So, 4x + 7(9-x) = 48, x = 5 ans.

$ItzDopeGirl$❣