A can do a piece of work in 14 days, while B can do in 21 days. They begin together. But, 3 days before the completion of work, A leaves off. Find the total number of days taken to complete the work.
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Answer:
1o.2 days (hopefully I am right I mean the answer sorta looks wrong to me)
Step-by-step explanation:
Let the no. of days b works be x days
=> no. of days A works = (x - 3) days
No. of days in which A completes the work = 14 days
Part of work done by A in 1 day = 1/14
No. of days in which B completes the work = 21 days
Part of work done by B in 1 day = 1/21
According to question,
[(x - 3)/14] + [x/21] = 1 (since 1 whole work is done)
[3x - 9 + 2x]/42 = 1
5x = 51
x = 10.2 days
Therefore the work is done in 10.2 days
HOPE IT HELPS
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