A can do a piece of work in 14 days while B can do in 21 days they join together but 3 days before the completion of work A leaves off find the total number of days taken to complete the work
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We will solve this using the LCM technique.
A takes 14 Days & B takes 21 Days. So, let the total work be LCM(14,21) = 42 Units
A -> 14 days = 3 Units/day
B -> 21 days = 2 Units/day
A + B = 5 Units/day
Now, for the last 3 days , only B worked as A left.
So, work done in the last three days = 2×32×3= 6 units
Work done by A & B together = 42–6 = 36 units
Time taken = 365365 = 7.2 days
Thus, TOTAL TIME = 3+7.2 = 10.2 Days
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