A can do a piece of work in 14 days, while B can do in 21 days. They begin together. But, 3 days before the completion of the work, A leaves off. Find the total number of days taken to complete
the work.
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Answer:
Read and write
Step-by-step explanation:
ANSWER
(A+B)
′
s1 day work
=
14
1
+
21
1
=
42
3+2
=
42
5
At the end, B works for 3 days so work done by B in 3 days=3×
21
1
=
7
1
.
Remaining work 1−
7
1
=
7
6
which is to be done by A and B.
42
5
of work (A+B) can do in 1 days
∴
7
6
of work (A+B) can do in
5/42
1
×
7
6
=7
5
1
days
∴ Time to complete the work
=3+7
5
1
=10
5
1
days.
Hope this helps you out ☺️☺️
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