Math, asked by mohyadav2kk9, 4 days ago

A can do a piece of work in 14 days while B can do in 21 days they began together and worked at if for 7 days then A fell ill and B had to complete the work in how many days was the work completed​

Answers

Answered by realanshuu
2

Answer:

Number of days A required to do piece of work = 14 days

Number of days B required to do piece of work = 21 days

∴ We can calculate, work done by A in 1 day = 1/14

Work done by B in 1 day = 1/21

Work done by A, B together in a one day = 1/14 + 1/21 = 5/42

∴ They can work together in 42/5 days.

A and B work for 6 days and the work completed by A and B in 6 days

= 6 × 5/42 = 5/7

∴ Work left = 1- 5/7 = 2/7

Number of days taken by B to complete the left over work

= 2/7 × 21 = 6 (21 is used because 21 is the days required by B to complete a piece of work).

Time taken to complete the work = 6 + 6 = 12days

Total time taken to complete the work =12day.

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