Math, asked by hrududeotale3901, 1 year ago

A can do a piece of work in 14 days while B can do it in 21 days they begin together and work at it for 6 days then a fell ill and and b had to complete the remaining work alone in how many days was the work completed

Answers

Answered by SKD11
4
A-14 Total work=42 (by lcm)
B-21
A-one day unit =3unit
B--------------------=2 unit
6 days together works = 6×5=30unit
remaining = 42 unit-30unit=12 unit
now B complt 12 unit/2 unit =6days
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