A can do a piece of work in 14 days while B can do it in 21 days.They worked together at it for 6 days and them A leaves .In how many days was the work completed?
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Step-by-step explanation:
(A+B)′s1 day work
=141+211=423+2=425
At the end, B works for 3 days so work done by B in 3 days=3×211=71.
Remaining work 1−71=76 which is to be done by A and B.
425 of work (A+B) can do in 1 days
∴76 of work (A+B) can do in 5/421×76=751days
∴ Time to complete the work
=3+751=1051days.
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