A can do a piece of work in 14 days while B can do it in 21 days. They began together and worked at it for 6 days. then, A fell ill and B had to complete the remaining work alone.In how many days was the work completed?
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A's one day work=1/14
B's one day work=1/21
{A+B} one day work=1/14 + 1/21 = 5/42
they both work 6 day =5/42 *6 = 5/7
B had to complete the remainig work=1 - 5/7=2/7
B had to complete the work=2/7 divided by 1/21
divide change into mutiply=2/7*21/1 = 6
total time taken =6+6=12
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