A can do a piece of work in 14 days ,while B can do it in 21 days.They begin together.But ,3 days before the compleation of work , A leaves off. Find the total numbers of days taken to compleat the work.
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A’s one day work =1/14
B’s one day work=1/21
(A+B)’s one day work =1/14+1/21=(3+2)/42 =5/42
(A+B) can do the work in =42/5 =8.4 days
They work together in =(8.4–3)= 5.4days
Work done by both in 5.4 days =(5/42)×5.4
=5×54/42×10= 9/7×2= 9/14 work.
Remaining work =1- 9/14=5/14.
1 work B can do in = 21 days
5/14 work B can do in =21×5/14 =15/2=7.5 days
Total days to complete the work=5.4+7.5
=12.9 days or 13 days. Answer.
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B’s one day work=1/21
(A+B)’s one day work =1/14+1/21=(3+2)/42 =5/42
(A+B) can do the work in =42/5 =8.4 days
They work together in =(8.4–3)= 5.4days
Work done by both in 5.4 days =(5/42)×5.4
=5×54/42×10= 9/7×2= 9/14 work.
Remaining work =1- 9/14=5/14.
1 work B can do in = 21 days
5/14 work B can do in =21×5/14 =15/2=7.5 days
Total days to complete the work=5.4+7.5
=12.9 days or 13 days. Answer.
CID brainliest as I need only one best answer to go to the next rank
ajuroy5:
answer is 51/5 days
yes this is wrong
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