A can do a piece of work in 14 days while B can do it in 21 days . they began together and worked at it for 6 days . then A fell ill and B had to complete the remaining work alone . in how many days was the work completed?
Answers
Answered by
15
Answer:
Step-by-step explanation:
A's one day work=1/14
B's one day work=1/21
{A+B} one day work=1/14+1/21=5/42
they both work 6 day =5/42*6=5/7
B had to complete the remainig work=1-5/7=2/7
B had to complete the work=2/7 divided by 1/21
divide change into mutiply=2/7*21/1=6
total time taken =6+6=12
jarpana2003:
pls mark as brainlist
Similar questions
Chinese,
6 months ago
Math,
11 months ago
Chemistry,
11 months ago
Math,
1 year ago
Social Sciences,
1 year ago