Math, asked by khurshed63, 11 months ago

A can do a piece of work in 15 days and B alone can do it in 10 days. B work at if for 5 days and then leave. A alone can finish the remaining work

Answers

Answered by homosapiens45
16

Given : A can do piece of work = 15 days

            B alone can do piece of work = 10 days


To find : How many days A required to finish the work alone.


Proof :

We have ,

B alone  can do piece of work = 10 days


∴ B 's 5 days work = 1/10 * 5 = 1/2


=> Remaining work = 1 - 1/2 = 1/2


∴  A can finish work = 15 * 1/2 = 7.5 days


Hence , A alone can finish the remaining work in 7.5 days


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