A can do a piece of work in 15 days and B can do the same work in 10 days. They work together for 5 days and then B leaves. A will finish the remaining work in how much days?
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Answer: 2.5 days
Step-by-step explanation:
Lets suppose the work to be completed is 100.
A finishes it in 15 days so his per day completion is 100/15= 6.6667% per day
B finishes it in 10 days so his per day completion is 100/10= 10% per day.
So in the first 5 days, they complete
= A + B
= (6.6667 × 5) + (10 × 5)
= 33.3333 + 50
= 83.333 % of work completed.
Leftover workload = 100- 83.3333% = 16.666667 %
Divide that by A's efficiency rate of 6.6667% = 16.6667/6.6667 = 2.4999 or 2.5 days or 3 days(conversion to whole days)
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