A can do a piece of work in 15 days and B can do the same work in 20 days. They worked together for 6
days, then B fell ill, so remaining work was completed by A. In how many days, A completed the work?
Answers
Answered by
6
Answer: 12 DAYS
Step-by-step explanation:
(A + B)'s 1 day's work
=1/15 + 1/10= 1/6
Work done by A and B in 2 days
= 1/6*2= 1/3
Remaining work
= 1− 1/3 = 2/3
NOW 1/15 WORK ID=S DONE BY A IN 1 DAY
Therefore 2/3 work will be done by A in
15* 2/3=10 days
Hence,the total time taken = 10+2= 12 days
HOPE IT HELPS YOU!!!!
Answered by
6
Answer:
In one day A can complete 1/25 of the work. And.
In one day B can complete 1/20 of the work.
Together they can complete 1/25+ 1/20 work in one day.
Hence in 5 days they can complete 5/25 + 5/20 work. ie = 9/20 work.
Remaining work is 1–9/20 work= 11/20 work
Hence B can complete the remaining 11/20 work in 11/20 / 1/20=11 days.
Step-by-step explanation:
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