A can do a piece of work in 15 days and B can finish it in 20 days.They work together for 5 days and then A goes away.In how many days will B finish the work
Answers
In one day A can complete 1/25 of the work.
And,
In one day B can complete 1/20 of the work.
Together they can complete 1/25+ 1/20 work in one day.
Hence,
In 5 days they can complete 5/25 + 5/20 work. ie = 9/20 work.
Remaining work is 1–9/20 work= 11/20 work
Hence,
B can complete the remaining 11/20 work in 11/20 / 1/20=11 days.
Answer:
this is your answer
Step-by-step explanation:
A's 1 day's work =
25
1
Similarly, B's 1 day's work =
20
1
A's and B's together 1 day's work
25
1
+
20
1
=
100
4
+
100
5
=
100
4+5
=
100
9
Their 5 day's work together = 5 x 1 day's work
1−
100
45
=
100
100
−
100
45
=
100
100−45
=
100
55
Now, this remaining work is done by B.
Let B takes x days to complete it.
20
1
×x=
100
55
⇒x=
100
55
×20
⇒x=
5
55
⇒x=11
Hence, B will finish the remaining work in 11 days.