A can do a piece of work in 15 days. B can do the same work in 12 days and C can
finish the same piece of work in 20 days. They started the work together for 2 days
and then B and C leaves. In how many days will A finish the remaining work?
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A=15---------------4
B=12------60--------5
C=20------------3
A+B+C=2×12=24
work left =36
A can finish work =36/4=9 days
Step-by-step explanation:
A can complete a work in =15 days
B can complete the same work in=12 days
C can complete the same work in=20 days
let the total work be 60
so one day work of A=4
one day work of B=5
one day work of C=3
if A,B and C work for 2days,then
the work completed=2×(4+5+3)=2×12=24
the work left =60-24=36
so A can finish the remaining work=36/4=9days
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