Question

A can do a piece of work in 16 days, B can do in 32 days and C can do in 48 days. After starting together, B left the work 6 days before the end of work and C left 8 days before finishing the work.​

Answer 1

Answer:

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Let the work be completed in= N- days.

Let the work be completed in= N- days.A- works for complete period.

Let the work be completed in= N- days.A- works for complete period.B- works for 8- days

Let the work be completed in= N- days.A- works for complete period.B- works for 8- daysC- works for (N-8) - days.

Let the work be completed in= N- days.A- works for complete period.B- works for 8- daysC- works for (N-8) - days.So N/16 + 8/32+ (N-8)/48= 1

Let the work be completed in= N- days.A- works for complete period.B- works for 8- daysC- works for (N-8) - days.So N/16 + 8/32+ (N-8)/48= 1=6N+ 24+ 2(N-8)= 96

Let the work be completed in= N- days.A- works for complete period.B- works for 8- daysC- works for (N-8) - days.So N/16 + 8/32+ (N-8)/48= 1=6N+ 24+ 2(N-8)= 96= 8N= 96–24+16= 88

Let the work be completed in= N- days.A- works for complete period.B- works for 8- daysC- works for (N-8) - days.So N/16 + 8/32+ (N-8)/48= 1=6N+ 24+ 2(N-8)= 96= 8N= 96–24+16= 88So N= 88/8

Let the work be completed in= N- days.A- works for complete period.B- works for 8- daysC- works for (N-8) - days.So N/16 + 8/32+ (N-8)/48= 1=6N+ 24+ 2(N-8)= 96= 8N= 96–24+16= 88So N= 88/8= 11-days.

Therefore work will be completed in = 11- days.

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