Math, asked by aryakurup, 11 months ago

A can do a piece of work in 16 days ,B can do it 12 days .With the help of C they can finish it in 4 days .Then c alone can do it in how many days?

Answers

Answered by Anonymous
34

Answer :-

C alone can do the same work in 9.6 days.

Solution :-

A can do a piece of work in 16 days

So A's one day work = 1/16

B can do the same work in 12 days

So B's one day work = 1/12

A, B, C can do the same work in 4 days

(A, B , C)'s one day work = 1/4

We know that

C's one day work = (A, B, C)'s one day work - A's one day work - B's one day work

= 1/4 - 1/16 - 1/12

= (12 - 3 - 4)/48

= (12 - 7)/48

= 5/48

C's one day work = 5/48

So C alone can do the same work in 48/5 days i.e 9.6 days.

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