A can do a piece of work in 18 days and B in 12 days together, But B left the work 3 days before its completion, in how Many days in all work completed
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in 26 days the all work completed
12-3=8
18+8=26 so the answer is 26
shahidansari786:
No, 26 isn't in the options
Answered by
1
Answer:
9 days
Step-by-step explanation:
A can do a piece of work in 18 days
A one day work is =1/18
B can do a piece of work in 12 days
B one day work is =1/12
A and B both together work for one day= 1/12+1/18
=5/36 part
let total work completed in x days
both work for (x-3) and A work alone 3 days
both work for (x-3) days =(x-3)5/36=5x-15/36
A alone three days work =3*1/18=1/6
as per give conditions
1/6+ 5x-15/36 =1
by LCM solving we will get
-9+5x/36=1
-9+5x=36
5x =45
x=45/5=9 days
Answer
work completed in 9 days
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