Math, asked by shahidansari786, 1 year ago

A can do a piece of work in 18 days and B in 12 days together, But B left the work 3 days before its completion, in how Many days in all work completed​

Answers

Answered by phaniraj57
0

in 26 days the all work completed

12-3=8

18+8=26 so the answer is 26


shahidansari786: No, 26 isn't in the options
pranithrahulspr: bulb!!!
pranithrahulspr: See my ans
shahidansari786: Nope 26 is worng, 9 days is correct
Answered by pranithrahulspr
1

Answer:

9 days

Step-by-step explanation:

A can do a piece of work in 18 days

A one day work is =1/18

B can do a piece of work in 12 days

B one day work is =1/12

A and B both together work for one day= 1/12+1/18

=5/36 part  

let total work completed in x days  

both work for (x-3) and A work alone 3 days  

 

both work for (x-3) days =(x-3)5/36=5x-15/36

A alone three days work =3*1/18=1/6  

as per give conditions  

1/6+ 5x-15/36 =1

by LCM solving we will get  

-9+5x/36=1

-9+5x=36

5x =45  

x=45/5=9 days

Answer

work completed in 9 days


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