Question

A can do a piece of work in 18 days; b can do the same in 24 days. A started alone but left the work after 8 days, then b worked at it for 6 days. C finished the remaining work in 11 days. C alone can do the whole work in?

Answer 1

We will use the LCM technique to solve this.

A takes 18 days to complete the task whereas B takes 15 days to complete.

Let the TOTAL WORK = 90 Units

So, A does 5 Units/day
B does 6 Units/day
B worked for 10 days and left the job. So, work done by B = 60 Units

Remaining Work = 30 Units.
Thus, A will take = 305 = 6 Days (Answer)

Answer 2

here is ur answer....