Question

A can do a piece of
work in 18 days. If bis 20% more
efficient than A. Then the number of days required by B do the same al piece of work is​

Answer 1

Answer:

15 days

Step-by-step explanation:

According to the question,

      A can do a piece of  work in 18 days and B is 20% more  efficient than A

∴ B required the number of days do the same al piece of work is​

= 18 × (100-20) % = 18 × 80% = 18 × $\frac{80}{100}$ = 14.4 ≈ 15 days