A can do a piece of work in 20 days and B can do a piece if work in 12 days.B worked at it for 9 days.in how many days A alone can finish the remaining work.
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A’s 1 day work=1/20
B’s 1 day work=1/12
Work done by B in 9 days=1/12*9
=3/4
Let no.of days for A to finish work be x
Total work done by A=x+9 days
3/4+1/20*(x+6)=1
3/4+(x+6)/20=1
84+4x/80=1
84+4x=80*1
84-80=4x
4/4=x
x=1
Therefore, Abalone can finish the work in another x+9=10 days
Hope it helps
B’s 1 day work=1/12
Work done by B in 9 days=1/12*9
=3/4
Let no.of days for A to finish work be x
Total work done by A=x+9 days
3/4+1/20*(x+6)=1
3/4+(x+6)/20=1
84+4x/80=1
84+4x=80*1
84-80=4x
4/4=x
x=1
Therefore, Abalone can finish the work in another x+9=10 days
Hope it helps
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