Question

A Can do a piece of work in 20 days and B Can do the same work in 25 days. They work together on it for 10 days. What fraction of work will be left ?

Answer 1

Step-by-step explanation:

A's 1 day's work = 25/1

Similarly, B's 1 day's work = 20/1

A's and B's together 1 day's work

+

20

1

=

100

4

+

100

5

=

100

4+5

=

100

9

Their 5 day's work together = 5 x 1 day's work

1−

100

45

=

100

100

−

100

45

=

100

100−45

=

100

55

Now, this remaining work is done by B.

Let B takes x days to complete it.

20

1

×x=

100

55

⇒x=

100

55

×20

⇒x=

5

55

⇒x=11

Hence, B will finish the remaining work in 11 days.

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