A can do a piece of work in 20 days and B in 16 days. they worked together for 5 days and then A left. In many days will B finish the remaining work?
Answers
Given A can do the work in 20 days and B can do it 15 days.
Then work done by A in one day =
20
1
And, work by B in one day =
15
1
Then, the work done by A & B in one day =
20
1
+
15
1
=
60
7
A & B done 6 days together then work done in A & B in 6 days =
60
7
×6=
10
7
Then friction of work left =1−
10
7
=
10
3
Then B can do
10
3
work =
10
3
×
1
15
=
2
9
=4
2
1
days.
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Step-by-step explanation:
A can do whole work in 20 days
A can do 1/20 part of work in 1 day
B can do work in 16 days
B can do 1/16 part of work in 1 day
A+B can do 1/20 +1/16 = 4+5/80 = 9/80 part of work in 1 day
In 5 days A+B can do =9/80 ×5 = 9/16 part of work
Remaining work=1- 9/16 = 7/16
B can do 1/16 part of work in 1 day
B can do 7/16 (= 7 ×1/16) part of work in
(7×1=) 7days