A can do a piece of work in 20 days and B in 16 days. they worked together for 5 days and then A left. In how many days will B finish the remaining work
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3
Answer:
In 1- day A and B can do= 1/20+ 1/25 = 9/100.
In 5- days both can do= 9/100 x 5 =45/100.
Number days required by A to finish the remaining work= (55/100)÷(1/20) = 11- days.
========================== Another method A does the work till the end and B does the work for 5- days only.
If the total work if finished in X- days, then
So X/20 + 5/25= 1
5X+ 20= 100
X= 80/5= 16.
So complete work is done in 16- days.
A alone does after B- left= 16–5= 11- days !!!
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