a can do a piece of work in 20 days B in 15 days and C in 12 days how soon can the work be done if a is assisted by b on one day and by c on the next alternately
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9 3 /8 in mixed form
days Work will be Completed
Step-by-step explanation:
First day A+B worked = 2+3 = 5 units
Second Day A + C Worked = 2 + 6 = 8 units
Third Day A + B Worked = 5 units
In one cycle work is completed = 13 units
It will continue at last, work will finish in
and 8 units of work is left.
Now, A will do with 'B' and they will complete 5 units.
Remaining 3 units will be done by A and C in
Total Time = 4 cycle 2 = 8 days
A + B = 1 days
A + C = 3/8 days
Thus, Total Time = 8 days + (A+B)'s days + (A+C)'s days
8 + 1 + 3/8
9 3/8
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