Question

a can do a piece of work in 20 days B in 15 days and C in 12 days how soon can the work be done if a is assisted by b on one day and by c on the next alternately ​

Answer 1

9 3 /8 in mixed form

days Work will be Completed

Step-by-step explanation:

First day A+B worked = 2+3 = 5 units

Second Day A + C Worked = 2 + 6 = 8 units

Third Day A + B Worked = 5 units

In one cycle work is completed = 13 units

It will continue at last, work will finish in

and 8 units of work is left.

Now, A will do with 'B' and they will complete 5 units.

Remaining 3 units will be done by A and C in

Total Time = 4 cycle 2 = 8 days

A + B = 1 days

A + C = 3/8 days

Thus, Total Time = 8 days + (A+B)'s days + (A+C)'s days

8 + 1 + 3/8

9 3/8