A can do a piece of work in 20 days,B in 30 days and C in 40 days . They start working together. A works for 2 days and leaves and B works for 4 days and leaves.How long does the work last
Answers
Answer:
28
Step-by-step explanation:
A efficiency 6
B efficiency 4
C efficiency 3
Total work 120
A+B+C=2 DAYS
B+C=4 DAYS
C=22 DAYS
TT=28...
- Detailed explanation is given in photo
Answer:
Step-by-step explanation:
A does (1/20)th of the work in 1 day.
B does (1/30)th of the work in 1 day.
C does (1/40)th of the work in 1 day.
In the first 4 days, A, B and C did 4[(1/20)+(1/30)+(1/40)] =4{6+4+3]/120 = 13/30th of the work.
In the next 2 days, B and C did 2[(1/30)+(1/40)] = 2*7/120 or 7/60th of the work.
So in the first 6 days the work done was (13/30)+(7/60) = (26+7)/60 = 33/60 or 11/20th of the whole. What remained to be don after the first 6 days was (9/20)th of the whole.
The remaining (9/20)the was done by C alone in (9/20)*(40/1) = 18 days.
Thus the whole work is done in 24 days from the start. Answer.